Question

determine the nature of roots of quadratic equation 2x+5√3x+9=0​

Answer 1

Answer:

${2x}^{2} +5 \sqrt{3x} + 9 \\ \\ a = 2 \\ b = 5 \sqrt{3 } \\ c = 9 \\ \\ discriminant = {b}^{2} - 4ac \\ = 75 - 72 \\ = + 3 > 0 \\ then \: the \: equation \: have \: \\ two \: real \: roots..$

Answer 2

Answer:

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Step-by-step explanation:

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