if a bar is perpendicular to b bar then
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given
A bar is perpendicular to b bar
so, A bar.B bar = 0 but A bar × B bar ≠ 0
then,
A bar [ A bar + B bar]
= A bar.A bar + A bar.B bar
= A²+0 ( since A bar.B bar = 0)
= A²
A bar[A bar + B bar ] = A²
.
. . Option B is correct✔
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Given , A bar is perpendicular to B
Therefore , A bar . B bar = 0 ( cos 90° = 0 )
A bar × B bar ≠ 0 ( sin 90° = 1 )
then,
A bar [ A bar + B bar]
= A bar.A bar + A bar.B bar
= A²+0 ( since A bar.B bar = 0)
= A²
⇒A bar[A bar + B bar ] = A²
Answer : B
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