Question

Determine the nature of roots of the quadratic equation ( x-2a) (x-2b)= 4ab. Write the answer fast then I will mark you brainliest .

Answer 1

Answer:

given equation is

(x-2a)(x-2b)=4ab

x²-2bx-2ax-4ab=0

x²+[-2(a+b)]x+(-4ab)=0

here A=0;B=-2(a+b);C=-4ab

determinent=B²-4AC

=[-2(a+b)]²-4(0)(-4ab)

=4(a+b)²-0

=[2(a+b)]²

we know that any x€R;x²>0

so [2(a+b)]²>0

determinent>0

so,roots of given equation are positive integers.

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hope it'll help you

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Answer 2

Answer:

pls find the answer in the attachment

Step-by-step explanation:

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