Determine the nature of the root x^2-2x+k=0;k>1

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Answer:
Step-by-step explanation:
x^2-2x+k=0
b2-4ac=(-2)^2-4k
=4-4k
=4(1-k)
if K>1
1-k<0
1-k is negative
hence the discrimination is -ve
so the roots are imaginary and unequal
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