Math, asked by preeti99699, 11 months ago

Determine the nature of the root x^2-2x+k=0;k>1
by  \: the \: formula \: b {}^{2}  - 4ac

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

x^2-2x+k=0

b2-4ac=(-2)^2-4k

=4-4k

=4(1-k)

if K>1

1-k<0

1-k is negative

hence the discrimination is -ve

so the roots are imaginary and unequal

Similar questions