Question

Determine the nature of the roots ​

Answer 1

Hey mate, here is your

solution.

We have,

${x}^{2} - \frac{1}{2} x + 16 = 0$

Now,

${b}^{2} - 4ac \\ { (\frac{1}{2} )}^{2} - 4 \times 1 \times \frac{1}{16} \\ \frac{1}{4} - \frac{1}{4} \\ \: \: \: \: 0$

Since,

${b}^{2} - 4ac = 0$

Therefore, the roots are real and equal.

Hope it helps...