Math, asked by sunildhurandhar933, 1 month ago

determine the nature of the roots for the quadratic equation √3x2+√2x-2√3=0

Answers

Answered by Anonymous
19

Answer:

  \sqrt{3}{x}^{2}  +  \sqrt{2}x - 2 \sqrt{3} = 0

comparing with ax^2+bx+c=0 we get,

a=root 3

b= root 2

c= 2 root 3

b2-4ac=(root2)^2-4(root 3)(2 root3)

b2-4ac=2-24

b2-4ac= -22

since b2-4ac > 0

therefore,

root are not real

hope it help you


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Answered by erumramzan52gmailcom
7

Answer:

b2-4ac

2 -4(√3×2√3)

2-4(6)

2-24

-22 imaginary root

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