determine the nature of the roots for the quadratic equation √3x2+√2x-2√3=0
Answers
Answered by
19
Answer:
comparing with ax^2+bx+c=0 we get,
a=root 3
b= root 2
c= 2 root 3
b2-4ac=(root2)^2-4(root 3)(2 root3)
b2-4ac=2-24
b2-4ac= -22
since b2-4ac > 0
therefore,
root are not real
hope it help you
Answered by
7
Answer:
b2-4ac
2 -4(√3×2√3)
2-4(6)
2-24
-22 imaginary root
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