Question

determine the nature of the roots for the quadratic question 3x²+​

Answer 1

Answer:

a= √3, b= √2, c= -2√3

D= b^2-4ac

= (√2)^2 - 4×√3×(-2√3)

= 2+24

= 26

D>0, 26>0

hence, the quadratic equation has two real distict roots