determine the nature of the roots for the quadratic question 3x²+
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Answer:
a= √3, b= √2, c= -2√3
D= b^2-4ac
= (√2)^2 - 4×√3×(-2√3)
= 2+24
= 26
D>0, 26>0
hence, the quadratic equation has two real distict roots
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