Question

determine the nature of the roots of the quadratic equation 2x²-3x-4=0​

Answer 1

Answer:

it has two distnct roots

Step-by-step explanation:

nature of roots=b^2-4ac

given,

         2x^2-3x-4=0--------equ1

we know

               ax^2+bx+c=0---------equ2

compare equ1 and equ2

a=2,b=-3,c=-4

d=b^2-4ac

 =(-3)^2-4(2)(-4)

 =9+32=41

therfore

b^2-4ac > 0

it has two distinct roots