Question

Determine the nature of the roots of the quadratic equation 2x² – 3x – 4 = 0.​

Answer 1

Answer:

The roots will be real and distinct

Step-by-step explanation:

a=2,b=3,c=4

d=b^2-4ac

d=3^2-4×2×(-4)

d=9+32

d=41

d>0

thus ,the roots will be real and distinct.

Answer 2

Answer :—

The Roots Will be Real and Distinct .

Given :—

• Quadratic equation ➤ 2x² – 3x – 4 = 0.

To Find :—

➤ Nature Of The Quadratic Equation .

Solution:—

The given quadratic equation is ;

2x² – 3x – 4 = 0 .

Comparing with the general form of the quadratic equation ax² + bx + c = 0 ,

we have ;

a = 2 , b = 3 , c = -4

Now,

The discriminant of the given quadratic equation will be given as ;

$\longmapsto\tt\bf$D = b² - 4ac

$\longmapsto\tt\bf$D = 3² - 4×2×(-4)

$\longmapsto\tt\bf$D = 9 + 32

$\longmapsto\tt\bf$ D = 41

$\longmapsto\tt\bf$D > 0

The discriminant of the given quadratic equation is greater than zero .

Thus , Its roots will be real and distinct .

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