Question

Determine the nature of the solutions to the equation: x2 + 2x - 4 = 0

Answer 1

Answer:

Real and unequal

Step-by-step explanation:

x2 + 2x - 4

a= 1

b=2

c=-4

D = b2 - 4ac

  = 2^2 - 4 * 1 * -4

  = 4 + 16

  = 20

Since, D>0

Thus, the nature of the roots is real and unequal.

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Answer 2

Solution →

x² + 2x - 4 = 0

We can write it as →

(1) x² + (2)x -4 = 0

By comparing this equation by ( ax²+ bx + c = 0)

a = 1, b = 2 , c = -4

We know that →

D = b²-4ac

D = (2)² - 4 × 1 × (-1)

D = 4 + 16

D = 20

Now, D > 0

So the nature of the roots of this equation is Real And unequal.

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