Question

Determine the no of moles present in 0.55 mg of electrons

Answer 1

1Kg=106[math]1Kg=106[/math]mgMass of an electron = 9.1×10−31[math]9.1×10−31[/math]Kg  

=9.1×10−25mg.[math]9.1×10−25mg.[/math]

Next,number of electrons(X) present in 0.55 mg :

0.55/(9.1×10−25)=0.604×1024[math]0.55/(9.1×10−25)=0.604×1024[/math]

Further ;

no of moles (n) = X/N[math]X/N[/math]  

N is Avogadro's constant .

=n=0.604×1024/(6.023×1023)=1.0034793