Question

determine the no of moles present in 0.55 mg of eletrons​

Answer 1

Mass of an electron = 9.1×10^-31 Kg

= 9.1×10^-25 mg .

Then , number of electrons (say X) present in 0.55 mg :

0.55/(9.1×10^-25) = 0.604×10^24

Further ;

no of moles (say n) = X/N

here N is Avogadro's constant .

=> n= 0.604×10^24/(6.023×10^23)

= 1.0034793 .

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