Question

Determine the number of protons,electrons,neutrons,valence electrons and valency in Oxygen atom (O) and oxygen ion.Compare the stability of an atom and ion (Atomic number of Oxygen is 8)

Answer 1

Answer:

Explanation:

In O atom,there are 8 electrons and 8 protons and 8 neutrons.

In O ion,there are 10 electrons and other two are same as the O atom.

O atom is stable as it has no charge.But the O ion is negative so..it is not stable.

Answer 2

Hi,

I am guessing you are from OOEHS...? I have the same question too! Anyway, enough talking, Lets jump straight into the answer!

Answer:

The no. of sub-atomic particles in the Oxygen Atom:-

Protons- 8 (as atomic no. is 8)

Electrons- 8 (as atomic no. is 8)

Neutrons-8 (as mass no. is 16 and so 16-8=8)

Valence Electrons:- (See Below)

To find Valence electrons, you have to do the electronic configuration,

E.C. of Oxygen atom- 2,6

As Valence Electron is the no. of electrons in the outer shell, Valence electrons of Oxygen- 6

Valency: (See Below)

To fulfill the Octet rule, the atom needs 2 more electrons. Hence, Valency of Oxygen is 2.

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The no. of sub-atomic particles in Oxide ion-( $Ox^{2-}$) (Thats the symbol)

No. of Protons and Neutrons remain the same.

As the ion has a negative charge, and as the symbol is O2- , it means that 2 negative subatomic particles more than the Oxygen Atom.

We know that no. of protons are 8:

So 8+2= 10

∴ 10 electrons are present

Valency: (See Below)

E.C.:2,8

8-8= 0

Therefore, Valency of Oxide ion is 0

Valence Electrons=8

Oxide Ion has fulfilled the Octet rule and Thus, it is more stable

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Well, thats it!

I know this is an Enable question and my answer is too long but thats just because of my explanation!

I hope you understood it!

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