Question

Determine the number of real roots of the
equation: (x^2 + 1)^2 - x^2 = 0
3



please answer ​

Answer 1

Answer:

(x2 + 1)2 - x2 = 0 ⇒ x4 + 2x2 + 1 - x2 = 0 ⇒ x4 + x2 + 1 = 0 Let x2 = y, ⇒ y2 + y + 1 = 0 D = b2 - 4ac = 0 = 12 - 4(1)(1) ∴ D = -3 < 0 Hence, the equation (x2 + 1)2 - x2 = 0 has no real roots.Read more on Sarthaks.com - https://www.sarthaks.com/879202/x-2-1-2-x-2-0-has-a-four-real-roots-b-two-real-roots-c-no-real-roots-d-one-real-root

Explanation:

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Answer 2

Answer:

Answer:THIS QUESTION IS NOT UNDERSTANDABLE.