Determine the oxidation state of the metal ion in [Co(NH3)3Cl3]−.
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Explanation:
oxidation state of metal is +2
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The oxidation state of the metal ion in [Co(NH₃)₃Cl₃]⁻ is 2:
- The given compound [Co(NH₃)₃Cl₃]⁻ is a type of coordination compound.
- We will assume the oxidation state of the metal ion (Co in this case) to be y.
- We know that the overall charge on the compound is -1.
- The compound contains two types of groups i.e. ammine (NH₃) which is neutral and has a charge of 0, Chlorine (Cl) which is negative and has a charge of -1.
- Now, we will equate the charge outside the bracket to the sum of the charges on the groups inside the bracket.
y + (0×3) + (-1×3) = -1
y + 0 - 3 = -1
y = 3 - 1
y = 2
Thus, the oxidation state of the metal ion in [Co(NH₃)₃Cl₃]⁻ will be +2.
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