determine the pd which must be applied to a 2kohm resistor in order that a current of 10mA may flow.
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Answered by
70
Answer: V= IR
Where I= 10mA= 10/1000=1/100= 0.01 ,R= 2 ohm
V=IR
V= 0.01 × 2
V= 0.02volts
Please give it 5
:. Explained
Answered by
32
Answer: here is your answer is 20V. Thank you.
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