Question

determine the percentage decrease in the weight of one quintal sugar when taken to the bottom of mine 1 km deep radius of the earth is 6400km

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Answer 1

Percentage decrease in weight will be 0.102 %

Explanation:

We have given the radius of the earth R = 6400 km

Depth d = 1 km

We know the variation of g due to depth

$g_d=g\times (\frac{R-d}{R})=9.8\times (\frac{6400-1}{6400})=9.79$

Now let the mass is m

Then weight on the surface of earth = mg = 9.8m

And weight bellow 1 km = 9.79 m

So percentage decrease in weight $=\frac{9.8m-9.79m}{9.79m}=1.021\times 10^{-3}=0.102$ %

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