Question

Determine the photon Energy
if the wavelength 4 650nm.​

Answer 1

Solution:-

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Given:-

Wavelength($\lambda$ ) = 650nm

=> 6.5 × 10^-7 m

To determine the energy of a photon is given by

E = h$\sf\dfrac{c}{\lambda}$

E = $\sf\dfrac{(6.626 × 10^{-34}Js)(3 × 10^{8}m/s)}{6.5 × 10^{-7}m}$

After solving this we will get,

E = $\sf{3.051 × 10^{-19}Joules}$

Hence, the energy of given photon is 3.051 × 10^-19 J.

Answer 2

Explanation:

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