Physics, asked by hudaifaabbas, 1 month ago

Determine the potential difference across a capacitor of capacitance 3 micro farad connected between 4 resistors of 3 ohm and a battery of 15 volt.​

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Answered by maheshsingha553
0

Answer:

Thus, the potential difference between the plates of both capacitors is VA - VB = Vbat. We have C1 = Q1/Vbat and C2 = Q2/Vbat, where Q1 is the charge on capacitor C1, and Q2 is the charge on capacitor C2. Let C be the equivalent capacitance of the two capacitors in parallel, i.e. C = Q/Vbat, where Q = Q1 + Q2.

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