Question

determine the power extended in the process when amount of heat generated while transferring 90000 coulombs of charge between two terminals battery of 40v in one hour.

Answer 1

Here charge transferred Q=90000 C, time t=1 hour = 60*60=3600 s and potential difference V=50 V.
        I=Q/t
        I=90000/3600
        I=25
Now V=IR
        50=25*R
        50/25=R
        2=R
Now electric  power=I²R
                               25*25*2
=1250

Answer 2

Answer:

Power expended in the process is 1KW.

Explanation:

Given

Q = 90000,

t = 1h = 3600s,

V = 40V

Now we need to use formula

I = Q/t

=> 90,000/3600

=> 25A

And

R = V/I

=> 40/25

=> 1.6ohm

Now as per question

H = I²Rt

=> 25² x1.6 x 3600

=> 25 x 25 x1.6 x 3600

=> 3600 x 10^5

Or 3600kj

and

P = I²R

=> 25 x 25 x 1.6

=> 1000 W

=> 1 KW.

Hence, power expended in the process is 1KW.