Determine the ratio in which the line 3x+y-9=0 divides the segment joining the points (1,3) and (2,7).
Answers
Answered by
2
ratio is -L11:L22
-(3+3-9):(6+7-9)
3:4
-(3+3-9):(6+7-9)
3:4
Answered by
38
Solution: Let's assume that equation 3x + y - 9 = 0 divides segment at ratio k : 1.
→ (2k + 1)/(k + 1); (7k + 3)/(k + 1) = x, y
By substituting value of x and y in equation.
→ 3[(2k + 1)/(k + 1)] + (7k + 3)/(k + 1) = 9
→ [(6k + 3) + 7k + 3]/(k + 1) = 9
→ 13k + 6 = 9k + 9
→ 4k = 3
→ k = ¾
Answer: Ratio is ¾
Similar questions