Question

Determine the set of values of k for which the following quadratic equation has real roots: 4x2−3kx+1=0

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Answer 1

Answer:

k=-4/3 and 4/3

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Answer 2

Answer:

$4x {}^{2} - 3kx + 1 \\ a = 4 \\ b = 3k \\ c = 1 \\ {b}^{2} - 4ac \\ - 3k {}^{2} - 4 \times 4 \times 1 \\ 9k {}^{2} - 16 \\ 9k {}^{2} = 16$

$k {}^{2} = \frac{16}{9} \\ k = \frac{ + }{ - } \sqrt{ \frac{16}{9} } \\ k = \frac{4}{3} or - \frac{4}{3}$

Step-by-step explanation:

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