Math, asked by guri7549, 3 months ago

Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12.
Determine the greatest 3-digit number exactly divisible by 8, 10 and 12.
The traffic lights at three different road crossings change after every 48 seconds.
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Answers

Answered by RajputVansh
7

Step-by-step explanation:

When we multiply 24 with 2, 3, 4 we get only 2 digits. Therefore multiply 24 with 5. Now we get the three digit number 120. Therefore 120 is the smallest three digit number divisible by 6, 8 and 12.

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Answered by gauravverma41
2

Answer:

firstly we find the LCM of 6,8,12 and the LCM is 24 it is the answer

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