Determine the smallest 3-digit number which is exactly divisible by 6, 8 and 12.
Determine the greatest 3-digit number exactly divisible by 8, 10 and 12.
The traffic lights at three different road crossings change after every 48 seconds.
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Step-by-step explanation:
When we multiply 24 with 2, 3, 4 we get only 2 digits. Therefore multiply 24 with 5. Now we get the three digit number 120. Therefore 120 is the smallest three digit number divisible by 6, 8 and 12.
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Answer:
firstly we find the LCM of 6,8,12 and the LCM is 24 it is the answer
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