Question

Determine the smallest number which when divided by 12 16 24 and 36 leaves remainder 7 in each case.

Answer 1

Subtract 7 from 12 16 24 36
And find hcf
12-7 =5
16-7=9
24-7=17
36-7=29
Hcf 5 5,9,17,29
9 1, 9, 17,29
17 1, 1, 17,29
29 1 1 1 29
1 1 1 1
Hcf = 5×9×17×29

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