determine the subsets of D = 1,3,5,7,9
Answers
Answered by
0
no
of subsets =2 power n
2power5=32
of subsets =2 power n
2power5=32
Answered by
1
Given ,
D = { 1 , 3 , 5 , 7 , 9 }
n ( D) = 5 .
We know that,
Power set is the set of all subsets of a set.
So, P ( Set ) = 2^n
Now,
p ( D) = 2^5 = 32 .
The subsets of D are
{ Ø }
{ 1 } ,
{ 3 }
{ 5 }
{ 7 }
{ 9 }
{ 1 , 3 }
{ 3 , 5 }
{ 5 , 7 }
{ 7 , 9 }
{ 1 , 5 }
{ 1 , 7 }
{ 1 , 9 }
{ 9 , 5 }
{ 9 , 3 }
{ 7 , 3 }
{ 1 , 3 , 5 }
{ 1 , 5 , 7 }
{ 1 , 7 , 9 }
{ 3 , 5 , 7 }
{ 3 , 7 , 9 }
{ 5 , 7 , 9 }
{ 1 , 3 , 7 }
{ 1 , 3 , 9 }
{ 1 , 5 , 9 }
{ 1 , 3 , 5 , 7 }
{ 1 , 3 , 7 , 9 }
{ 3 , 5 , 7 , 9 }
{ 1 , 3 , 5 , 7 , 9 }
These are some subsets. I have written nearly 20 subsets , but you can find 32 .
D = { 1 , 3 , 5 , 7 , 9 }
n ( D) = 5 .
We know that,
Power set is the set of all subsets of a set.
So, P ( Set ) = 2^n
Now,
p ( D) = 2^5 = 32 .
The subsets of D are
{ Ø }
{ 1 } ,
{ 3 }
{ 5 }
{ 7 }
{ 9 }
{ 1 , 3 }
{ 3 , 5 }
{ 5 , 7 }
{ 7 , 9 }
{ 1 , 5 }
{ 1 , 7 }
{ 1 , 9 }
{ 9 , 5 }
{ 9 , 3 }
{ 7 , 3 }
{ 1 , 3 , 5 }
{ 1 , 5 , 7 }
{ 1 , 7 , 9 }
{ 3 , 5 , 7 }
{ 3 , 7 , 9 }
{ 5 , 7 , 9 }
{ 1 , 3 , 7 }
{ 1 , 3 , 9 }
{ 1 , 5 , 9 }
{ 1 , 3 , 5 , 7 }
{ 1 , 3 , 7 , 9 }
{ 3 , 5 , 7 , 9 }
{ 1 , 3 , 5 , 7 , 9 }
These are some subsets. I have written nearly 20 subsets , but you can find 32 .
Similar questions