Determine the the number nearest to 100000 but greater than 10000 which is exacly divisible by each of 8 ,15 ,21.
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Answer:
100800
Step-by-step explanation:
first find lcm of 8 15 21
=840
then divide 100000 by 840 remainder is 40
then subtract 40 from 840
that is 800
then add 100000 and 800
= 100800 ANS
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