determine the value of a if g(t)=1-2t is the factor of the following equation f (t) =4t ^4 -at^3+2t^2+4t+3
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Step-by-step explanation:
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Answer:-46
Step-by-step explanation:
g(t)=0
Then,1-2t=0
2t=1
t=1/2
f(t)=4t^4-at^3+2t^2+4t+3
f(t)=0
4t^4-at^3+2t^2+4t+3=0
4(1/2)^4-a(1/2)^3+2(1/2)^2+4(1/2)+3=0
4*1/16-a*1/8+2*1/4+4/2+3=0
4/16-a/8+2/4+2+3=0
1/4-a/8+1/2=-5
2+a+4/8=-5
6+a=-40
a=-46
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