Question

Determine the value of a if the system of linear equation 3x + 2y - 4=0, ax-y-3=0

Answer 1

Answer:

Step-by-step explanation:

Given equations are,

3x + 2y -4 = 0 or y = -3x/2 + 4,

px - y - 3 =0 or y = px - 3,

compare both equation to y = mx + c,

so m1 = -3/2 and m2 = p,

if both equation are perpendicular then,

m1 m2 = -1,

-3/2 * p = -1,

p = 2/3,

so the value of p = 2/3,

Hope it helps.