Math, asked by 8877715103, 1 year ago

determine the value of 'k' for which the following system of equation has no solution.
kx+2y-1=0. 5x-3y+2=0.

Answers

Answered by adityakjha24
2
for no solution

a1/a2 = b1/b2

k/5 = 2/-3

k = -10/3
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Answered by akhileshawasthi1976
2

Answer:

value of k = -10/3

Step-by-step explanation:

explanation is in the attachment

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