determine the value of 'k' for which the following system of equation has no solution.
kx+2y-1=0. 5x-3y+2=0.
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for no solution
a1/a2 = b1/b2
k/5 = 2/-3
k = -10/3
a1/a2 = b1/b2
k/5 = 2/-3
k = -10/3
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Answer:
value of k = -10/3
Step-by-step explanation:
explanation is in the attachment
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