Math, asked by utshab, 2 months ago

Determine the value of k for which the roots of the equation 3 kx² = 4 (kx - 1) is real and equal​

Answers

Answered by vipashyana1
0

Answer:

k=3

Step-by-step explanation:

3kx²=4(kx-1)

3kx²-4(kx-1)=0

3kx²-4kx+4=0

a=3k, b=(-4k), c=4

Discriminant=0

b²-4ac=0

(-4k)²-4(3k)(4)=0

16k²-48k=0

16k(k-3)=0

k-3=0/16k

k-3=0

k=3

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