Math, asked by MilanMilan15, 8 months ago

Determine the value of k if 8k+4, 6k-2 and 2k-7 are the three consecutive terms of an AP *​

Answers

Answered by nancygulia1234
1

Answer:

8k+4=6k-2 , 8k-6k = -2-4 , 2k = -6 , k = -3

Answered by ANSHURAJ2123
1

Answer:

if three numbers a,b,c are in ap then b = a+c/2

therefore, 6k-2 = (8k+4+2k-7)/2

12k-4 = 10k -3

12k-10k = -3+4

2k = 1

k = 1/2

Step-by-step explanation:

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