Determine the value of k if 8k+4, 6k-2 and 2k-7 are the three consecutive terms of an AP *
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Answered by
1
Answer:
8k+4=6k-2 , 8k-6k = -2-4 , 2k = -6 , k = -3
Answered by
1
Answer:
if three numbers a,b,c are in ap then b = a+c/2
therefore, 6k-2 = (8k+4+2k-7)/2
12k-4 = 10k -3
12k-10k = -3+4
2k = 1
k = 1/2
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