Question

determine the value of k in each of the following quadratic equation, for which the given value of x is the root of the given quadratic: 6x2+kx-√6=0 ; x= -√3/2​

Answer 1

Answer:

If x=-√3/2 is a root of the equation 6x^2+Kx-√6, then

6(-√3/2)^2+k(-√3/2)-√6=0

6×3/4-√3k/2-√6=0

9/2-√6=√3k/2

k=(9-2√6)/√3=3√3-2√2 Ans