Determine the value of 'k' such that (x-2) is a factor of 2 × x cube -6 × x square + kx - 2
Answers
Answered by
3
Hi there !
p(x) = 2x³ -6x² + kx - 2
x-2 is a factor of p(x)
x - 2 = 0
x = 2
p(2) = 0
p(2) = 2 ×2³ - 6× 2² + 2k -2
16 - 24 + 2k - 2 = 0
-10 + 2k
2k = 10
k = 10/2
k = 5
p(x) = 2x³ -6x² + kx - 2
x-2 is a factor of p(x)
x - 2 = 0
x = 2
p(2) = 0
p(2) = 2 ×2³ - 6× 2² + 2k -2
16 - 24 + 2k - 2 = 0
-10 + 2k
2k = 10
k = 10/2
k = 5
puransbohra975:
Thanks a lot
welcome !
Similar questions