Question

determine the value of k such that x+3is a factor of kxcube + x square -22x - 21​

Answer 1

Answer:

sorry

Step-by-step explanation:

but mark me as always brilliant

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

∵ x + 3 is a factor of polynomial p(x) = kx² + x² - 22x - 21

∴ By factor theorem, p(-3) = 0

Now, substituting the value of x

p(x) = kx² + x² - 22x - 21

p(-3) = k(-3)³ + (-3)² - 22(-3) - 21 = 0

⇒ -27k + 9 + 66 - 21 = 0

⇒-27 + 54 = 0

⇒ 27k = 54

⇒ k = 54 ÷ 27

⇒ k = 2 Ans.