Question

Determine the value of magnetic field (in mt) at the centre of a 20 cm long solenoid, of the solenoid has 200 turns and carrying a current of 4

a.

Answer 1

Answer:

MAGNETIC FIELD ( B ) = 0.5 Mini Tesla ( mT )

Explanation:

★ MAGNETIC FIELD ★

★ GIVEN ;

» Length of Solenoid ( L ) = 20 cm

» No. of turns ( N ) = 200

» No. of turns per unit length ( n ) = N / L = 200 / 20 × 10-² = 100

» Current in the Wire ( i ) = 4 A

» Permeability Constant ( μ° ) = 4π × 10^-7

★ MAGNETIC FIELD ( B ) = ???

_____ [ BY USING FORMULA ] _____

[ $B\: = \: μ°\: \times \: n \: \times \: i]$

★ B = 4π × 10^-7 × 100 × 4

» B = 4π × 400 × 10^-7

» B = 1600 π × 10^-7

» B = 5024 × 10^-7

★ MAGNETIC FIELD ( B ) = 502 μT

----------------------- [ OR ] ---------------------

★ MAGNETIC FIELD ( B ) = 0.5 m T

_______________________________________

ANSWER :- MAGNETIC FIELD IN CURRENT CARRYING SOLENOID OF 4 AMPERE IS ;

★ MAGNETIC FIELD ( B ) = 0.5 mT ★