Question

Determine the value of the q and p

x^{2} -qx-28=(x+7)(x-p)

Answer 1

Answer:

$x {}^{2} - qx - 28 = (x + 7)(x + ( - 4)) \\ x {}^{2} - qx - 28 = x {}^{2} + 3x + 7 \times ( - 4) \\ x {}^{2} - qx - 28 = x {}^{2} + 3x - 28 \\ p = - 4 \: \: \: and \: q = - 3$