Determine the values of a and b so that the following system of linear equations have infinitely many solutions
(2a – 1)x + 3y – 5 = 0
3x + (b – 1)y – 2 = 0
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Determine the values of a and b so that the following system of linear equations have infinitely many solutions
(2a – 1)x + 3y – 5 = 0
3x + (b – 1)y – 2 = 0
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HI MATE
Step-by-step explanation:
Answer
Given
(2a−1)x+3y−5=0
3x+(b−1)y=2
Since they have infinite no. of solution ,
3
2a−1
= b−1 3
= −2 −5 3
2a−1
=
b−1 3
= 2 5
4a−2=15
a= 4 17
6=5b−5
5b=11
b= 5 11
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