Math, asked by Anonymous, 1 month ago

Determine the values of a and b so that the following system of linear equations have infinitely many solutions
(2a – 1)x + 3y – 5 = 0
3x + (b – 1)y – 2 = 0​

Answers

Answered by unknowngirl1182
7

Answer:

Determine the values of a and b so that the following system of linear equations have infinitely many solutions

(2a – 1)x + 3y – 5 = 0

3x + (b – 1)y – 2 = 0

,

Attachments:
Answered by iamPriya1136
0

Answer:

HI MATE

Step-by-step explanation:

Answer

Given  

(2a−1)x+3y−5=0

3x+(b−1)y=2

Since they have infinite no. of solution ,

3

2a−1

=  b−1 3

​ =  −2 −5 3

2a−1

=  

b−1 3

​ =  2 5

 

4a−2=15

a= 4 17

 

6=5b−5

5b=11

b=  5 11

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