Determine the values of emitter current
and collector current of a transistor
having a DC=0.98 and collector to base
leakage current ICBO=4uA. The base
current is 50uA.
Answers
Answered by
0
Answer:
Given, That the current gain is 0.98
The change in emitter current is I
e
=5mA
Therefore the change in collector current is I
c
=0.98×I
e
=0.98×5=4.9mA
Therefore the correct option is A.
Explanation:
plz mark it as brainleast
Answered by
0
beta = Ic/Ib
Ic = 40 mA
Therefore Ib = 40 mA/100 = 0.4mA
Ie = Ic+Ib = 40 +0.4 = 40.4 mA
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