Determine the values of k for which the quadratic equation x^2+5kx+16=0 has real and equal roots
Answers
Answered by
2
Solution :
Compare given Quadratic equation
x²+5kx+16 = 0 with ax²+bx+c = 0 ,
we get
a = 1 , b = 5k , c = 16
Now ,
discriminant ( D ) = 0
[ Roots are real and equal ]
b² - 4ac = 0
=> ( 5k )² - 4×1×16 = 0
=> (5k)² = 64
=> 5k = ± √64
=> 5k = ± 8
=> k = ±8/5
•••
Compare given Quadratic equation
x²+5kx+16 = 0 with ax²+bx+c = 0 ,
we get
a = 1 , b = 5k , c = 16
Now ,
discriminant ( D ) = 0
[ Roots are real and equal ]
b² - 4ac = 0
=> ( 5k )² - 4×1×16 = 0
=> (5k)² = 64
=> 5k = ± √64
=> 5k = ± 8
=> k = ±8/5
•••
Similar questions