Question

Determine the vector product of f¹ = 2i+3j-4k and f²=--2j+3k ​

Answer 1

a Given, = 2i^ +3j^ + 4k^b

and = i^ - 2j^ + k^

So scalar product a

= (2i^ + 3i^ — 4k^)(i — 2j^ + k^)

= 2.1+3(-1) = 4(1)

= 2-5-4 [Here i^.i^ = 1,j^j^ = 1,k^.k^ = 1] = 2 - 10

= -8.