determine two consecutive multiple of 3 whose product is 270. (quadratic equation )
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Hey there!
Let the two multiples be x, x +3
[ they are consecutive multiples, consecutive multiples of n differ by n ]
So
x(x+3)=270
x²+3x-270=0
x²+18x-15x-270=0
x(x+18)-15(x+18)=0
(x-15)(x+18)=0
x=15
considering numbers are positive
There fore numbers are 15,15+3=15,18
hope helped !
Let the two multiples be x, x +3
[ they are consecutive multiples, consecutive multiples of n differ by n ]
So
x(x+3)=270
x²+3x-270=0
x²+18x-15x-270=0
x(x+18)-15(x+18)=0
(x-15)(x+18)=0
x=15
considering numbers are positive
There fore numbers are 15,15+3=15,18
hope helped !
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