Question

Determine two consecutive multiples of 3 whose product is 270.

Answer 1

SOLUTION :  

Let the two consecutive multiples of 3 are  3x and 3x + 3

A.T.Q

3x(3x + 3) = 270

x(3x + 3) = 270/3

x(3x + 3) = 90

3x² + 3x = 90

3x² + 3x - 90 = 0

3(x² + x - 30) = 0

x² + x - 30 = 0

x² + 6x - 5x - 30 = 0

[By middle term splitting]

x(x + 6) - 5(x + 6) = 0

(x + 6)(x - 5) =0

(x + 6) = 0 (x - 5) =0

x = - 6 or x = 5

Since, x can't be negative, so x ≠ - 6  

Therefore x = 5

first consecutive multiple = 3x = 3× 5 = 15

second  consecutive multiple = 3x + 3 = 3 × 5 + 3 = 15 + 3 = 18

Hence, the two consecutive multiples of 3 are 15 and 18 .

HOPE THIS  ANSWER WILL HELP YOU..

Answer 2

HEY BUDDYY!!!!!!!...

=> given=> let the two consecutive(two no with definite sucession)..be 'x', 'x+3'

x(x+3) = 270..

$x^{2}$ + 3x - 270= 0

$x^{2}$ +18x -15x -270 = 0

x(x+18)-15(x+18)= 0

(x+18)(x-15) = 0

x + 18 = 0

x = -18..

x = +15...,,

consider the x to be positive,,

hence,, two consecutive numbers with product as 270, are 15 and 18.....