Determine wheather the reaction
with the following ∆H and ∆S.
value are spontaneous or Non-Spontaneous State
wheather they are exothermic or endothermic.
a] ∆H = -110kj and ∆S - +40 Kj at 400k
b] ∆H = +50kj and ∆S = -130kj at 250k
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Explanation:
for exo Or endo we directly say by seeing ∆H ,if it is negative then it should be exo nd vice - versa
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