Question

Determine whether given cvalue of x is a zero x^2-7x-3,x=-1/3

Answer 1

Answer:

-1/3 is not zero of the polynomial

Step-by-step explanation:

${x}^{2} - 7x - 3 =0 \\ x = - \frac{ 1}{3} \\ = ( { - \frac{1}{3}) }^{2} - 7( - \frac{1}{3} ) - 3 \\ = \frac{1}{9} + \frac{7}{3} - 3 \\ = \frac{1 + 21 - 27}{9} \\ = - \frac{5}{9}$

-1/3 is not zero of the polynomial