Determine whether the given sequence is A.P or not?
5,12,19,26..
Answers
Answered by
22
Step-by-step explanation:
Here first term a=5 and common difference
d=12−5=7
Suppose nth term of the A.P. is 145
Now, T
n
=a+(n−1)d
∴145=5(n−1)(7)
∴145−5=7(n−1)
∴140=7(n−1)
∴20=n−1∴n=21
Answered by
33
Answer:
In given A.P. t1=5,t2=12,t3=19,t4=26
Step-by-step explanation:
=t2-t1
=12-5
d=7
=t3-t2
=19-12
d=7
=t4-t3
=26-19
=7
common difference between 5,12,19,26.. is 7.
Therefore, given sequence 5,12,19,26... is an A.P.
rudramhatrerudra497:
hi
thnx
for
answer
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