Determine whether the given values of x are zeroes of the given polynomial or not:x^2+6x+5;x=-1;x=-5
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Let p(x) = x2 + 6x + 5;
Put x = -1
⇒ p(-1) = (-1)2 + 6(-1) + 5 = 1 - 6 + 5 = 0
Put x = -5
p(-5) = (-5)2 + 6(-5) + 5 = 25 - 30 + 5 = 0
Therefore the given value of x is a zeroes of the given polynomial
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