determine whether(x-1) 2x^3+5x^2-10x+4
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Answered by
3
g(x) => x - 1 = 0 => x = 1
f(x) = 2x³ + 5x² - 10x + 4
= 2(1)³+5(1)²-10(1)+4 = 2+5-10+4= 11-10=1≠0
=> x-1 is not a factor of 2x³+5x²-10x+4
f(x) = 2x³ + 5x² - 10x + 4
= 2(1)³+5(1)²-10(1)+4 = 2+5-10+4= 11-10=1≠0
=> x-1 is not a factor of 2x³+5x²-10x+4
Answered by
3
Hola
Here is your answer -
Given -
p(x) - 2x³+ 5x² - 10x + 4
q(x) - x -1
x - 1 = 0
so, x = 1
Substuting x = 1 in p(x)
= 2(1)³ + 5(1)² - 10(1) + 4
= 2 + 5 - 10 + 4
= 7 - 6
= 1
No, it's not a factor since the obtained number is not zero, if it is zero then it is the factor.
Hope it helps
Here is your answer -
Given -
p(x) - 2x³+ 5x² - 10x + 4
q(x) - x -1
x - 1 = 0
so, x = 1
Substuting x = 1 in p(x)
= 2(1)³ + 5(1)² - 10(1) + 4
= 2 + 5 - 10 + 4
= 7 - 6
= 1
No, it's not a factor since the obtained number is not zero, if it is zero then it is the factor.
Hope it helps
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