Question

determine which of the following polynmials has (x+1) a factor x3 +x2 +x+1

Answer 1

Hello! dear,

Your answer goes like this ...


STEP:1: Put the divisor =0
                  x+1=0
                  x=-1

STEP:2: Let p[x]=x³+x²+x+1
                   Putting x=-1
                      p[-1]=[-1]³+[-1]²+[-1]+1
                    ⇒ -1+1-1+1
                      ⇒"0".

Thus the remainder =p[-1]=0
Since,Remainder is zero,x+1 is a factor of x³+x²+x+1.


Thank you dear,

Hope It helps.

Answer 2

f(x) =x-1 =0=-1.
f(-1)=-1³+-1²+-1+1=0..
Or,-1+1-1-1=0.
Or,2-2=0=0=0.
Its a factor,. So...

HOPE THIS HELPS!!