Question

Determine without actual division whether x+ 1 is a factor of x^3 + x^2.​

Answer 1

Answer:

Yes

Step-by-step explanation:

For 0 of x+1

x+1=0

x=-1

$p( - 1) = ( { - 1}^{3} ) + ( { - 1}^{2} ) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (by \: remainder \: theorem)\: \\ = > - 1 + 1 \\ = > 0$

Since, p(x)=0

Therefore, x+1 is a factor of p (x) [By factor theorem]