determine x+1 is a factor of x³-2x²-(2+√2)x-√2 or not
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1
Answer:
iv)x³−x²−(2+2)x+2=(−1)3−(−1)2−(2+2)(−1)+2=−1−1+2−2+2=0
This is zero. Then x+1 is the factor of equation
Answered by
0
Answer:
we know that x+1=0
so,x=-1
By substituting the value in the equation
(-1)^3 - 2(-1)^2 - (2+√2)-1 - √2
(-1) -(2) +2 -(√2) -√2
=0
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